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Q1-3. These questions are about the pressure of air inside a bike tyre:

bike wheels

 1. Which of these sentences best explains the change in pressure if the tyre is heated?

  • A. The pressure increases because there are more particles of air inside the tyre.
  • B. The pressure increases because the particles hit the sides harder and more often.
  • C. The pressure decreases because there are more spaces between the particles of a hot gas.
  • D. The pressure decreases because the particles move faster so do not hit the sides so frequently.

2. Which of these rows describes the change in pressure and particle speed if the temperature is kept constant, but more air is pumped into the tyre?

Pressure Particle Speed
A
increases stays the same
B
increases increases
C
stays the same stays the same
D
stays the same increases

3. When a cyclist sits on the bike, the tyre is compressed. Assuming the temperature remains constant, how does this compression change the volume of the tyre and the pressure in the tyre?

Volume Pressure
A
increases stays the same
B
increases increases
C
decreases stays the same
D
decreases increases

4. As any gas is cooled, the particles slow down. At what temperature do the particles have the least kinetic energy?

  • A. 0 °C
  • B. -100 °C
  • C. -273 °C
  • D. -373 °C
5+6. These questions are about the kelvin scale of temperature.

5. What is -173 °C in kelvin?

  • A. 100 K
  • B. 73 K
  • C. -173 K
  • D. -346 K

6. What is 400 K in °C?

  • A. 673 °C
  • B. 173 °C
  • C. 127 °C
  • D. -127 °C
7+8. A sealed gas syringe contains a volume of 30 cm3 of gas at a pressure of 100 kPa. sealed gas syringe

7. The syringe is pulled out slowly, increasing the volume to 75 cm3 whilst the temperature remains constant.

What is the new pressure in the gas?

  • A. 250 kPa
  • B. 150 kPa
  • C. 66 kPa
  • D. 40 kPa

8. At what volume would the pressure be 125 kPa?

  • A. 18 cm3
  • B. 24 cm3
  • C. 38 cm3
  • D. 50 cm3
An empty metal drinks bottle contains air at 300 K and at a pressure of 1 x 105 Pa. (the volume remains constant). drinks bottle

9. What is the pressure in pascals when the bottle is left in strong sunlight and the temperature reaches 350 K?

  • A. 1.2 x 105
  • B. 8.6 x 105
  • C. 8.6 x 104
  • D. 3.5 x 105

10. At what temperature will the pressure be 9 x104 Pa?

  • A. 270 °C
  • B. 60 °C
  • C. 24 °C
  • D. -3 °C
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Question 1:

When a tyre is heated:

Correct explanation: B — “The pressure increases because the particles hit the sides harder and more often.”


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 2:

Let’s break this down:

That matches: Pressure increases, Particle speed stays the same → option A.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 3:

Let’s reason through:

So: Volume decreases, Pressure increases → option D.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 4:

The particles have the least kinetic energy when they are as cold as possible — that is, at absolute zero.

Absolute zero is:

0 K=−273 °C

At this temperature, particle motion (in classical terms) has the minimum kinetic energy.

So the correct choice is:
C) -273 °C


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 5:

To convert from Celsius to kelvin:

T(K)=T(°C)+273

Here:

−173+273=100 K

So the answer is A) 100 K.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 6:

To convert from kelvin to Celsius:

T(°C)=T(K)−273

Here:

400−273=127 °C

So the answer is C) 127 °C.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 7:

We can use Boyle’s Law at constant temperature:

P1V1=P2V2

Given:

P1=100 kPa, V1=30 cm3, V2=75 cm3

100×30=P2×75

3000=P2×75

P2=3000/75=40 kPa

Correct answer: D) 40 kPa.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 8:

We continue with Boyle's Law from the previous setup:

P1V1=P2V2

With P1=100 kPa, V1=30 cm3, and P2=125 kPa:

100×30=125×V2

3000=125×V2

V2=3000/125=24 cm3

The correct answer is B) 24 cm³.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 9:

We can use the pressure law (Gay-Lussac’s law) for a gas at constant volume:

P1/T1=P2/T2

Given:

P1=1×105 Pa, T1=300 K, T2=350 K

P2=P1×T2 / T1

P2=1×105×350/300

P2=1×105×1.167

P2≈1.167×105 Pa

This is closest to 1.2×105 Pa in the options given.

Answer: A) 1.2×105 Pa.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 10:

We use the pressure law again at constant volume:

P1/T1=P2/T2

Given:

P1=1×105 Pa, T1=300 K ,P2=9×104 Pa

T2=T1×P2 / P1

T2=300×9×104 / 1×105

T2 = 270 K

Now convert to Celsius:

T(°C)=270−273=−3 °C

Correct answer: D) -3 °C.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.