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2. Elements in Group 7 have similar chemical reactions because they have the same number of ...
3. The order of reactivity of the Halogens from most to least reactive is:
4+5. Predict the colour and the state of astatine given the following information:
6. Information on the melting and boiling points of some of the group 7 elements is given below. Use the information to predict a value for the boiling point of iodine.
7. Which one of the following reactions will take place?
Q8-10. Chlorine gas is bubbled into sodium bromide solution.
The sodium bromide solution changes color indicating a reaction.
8. The reaction between chlorine and sodium bromide is a ...
9. This reaction occurs because ...
10. The chemical equation for this reaction is ...
Question 1:
Let’s review the halogens.
Halogens are the elements in Group 17 of the periodic table (F, Cl, Br, I, At, Ts). Key properties:
They are non-metals
They exist as diatomic molecules in their elemental state (F₂, Cl₂, Br₂, I₂, At₂ in theory)
They are highly reactive
Given these facts, the correct description is: A. non-metal elements composed of diatomic molecules
Answer: A ✅
*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret. Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.
Question 2:
Let’s think about why Group 7 (the halogens) have similar chemical properties.
Chemical properties are mainly determined by the number of electrons in the outermost shell — also called the valence electrons.
Group 7 elements all have 7 valence electrons, which makes them react in similar ways (e.g., gaining 1 electron to form a -1 ion, or sharing in covalent bonds).
A: electron shells — this is incorrect, because they have different numbers of shells as you go down the group.
B: electrons — incorrect, total electrons change with atomic number.
C: outer shell electrons — correct, same number (7) in the outermost shell.
D: protons — incorrect, proton number is different for each element.
So the correct answer is C.
Answer: C ✅
Question 3:
We know that in Group 7 (halogens), reactivity decreases as you go down the group. This is because:
Atoms get larger
The outer shell electrons are farther from the nucleus
It becomes harder to attract an extra electron (lower electron affinity)
So from top (most reactive) to bottom (least reactive): Fluorine > Chlorine > Bromine > Iodine
This matches option A.
Question 4 + 5:
Let’s look at the pattern for the halogens from fluorine to iodine:
Fluorine: yellow gas
Chlorine: green gas
Bromine: red-brown liquid
Iodine: grey solid
As we go down the group:
State changes from gas → liquid → solid (molecular weight and van der Waals forces increase)
Colour gets darker: yellow → green → red-brown → grey (darkening trend)
Extending to astatine (below iodine):
State should be solid at room temperature (even more solid than iodine, metallic-looking possibly)
Colour should be darker than grey, likely black (often described as black or dark metallic)
So predicted: black, solid
Answer: black solid ✅
Question 6:
Melting point of iodine = 114°C
Boiling point must be higher than 114°C
From the options (85, 100, 180, 300), only 180 and 300 are above 114°C
Looking at the pattern (boiling points go up by smaller amounts as you go down the group), 180°C is the most reasonable choice
Answer: 180°C ✅
Question 7:
Let's recall the reactivity series for halogens:
Most reactive → Least reactive Fluorine > Chlorine > Bromine > Iodine
A more reactive halogen can displace a less reactive halogen from its compound.
Check each option:
A. bromine + potassium iodide → potassium bromide and iodine
Bromine is more reactive than iodine ✅
Bromine will displace iodine from potassium iodide ✅
Reaction happens ✅
B. bromine + potassium chloride → potassium bromide and chlorine
Bromine is less reactive than chlorine ❌
Bromine cannot displace chlorine ❌
C. iodine + potassium chloride → potassium iodide and chlorine
Iodine is less reactive than chlorine ❌
No reaction ❌
D. iodine + potassium bromide → potassium iodide and bromine
Iodine is less reactive than bromine ❌
✅ Only A will take place.
Answer: A
Question 8:
Let's think through the reaction:
Chlorine gas (Cl₂) is bubbled into sodium bromide solution (NaBr).
Chlorine is more reactive than bromine, so it will displace bromine from sodium bromide.
The reaction is:
Bromine is produced, which gives the solution a brown/orange color.
This is a displacement reaction (a more reactive element displaces a less reactive one from a compound.
D. displacement — ✅ correct
Answer: D
Question 9:
The reaction happens because chlorine displaces bromine from sodium bromide.
For displacement to occur, the free halogen (chlorine) must be more reactive than the halogen in the compound (bromine).
That means: Chlorine is more reactive than bromine ✅
A says "chlorine is more reactive than sodium bromide" — sodium bromide is a compound, not an element, so this statement is incorrectly phrased (reactivity series compares elements, not compounds) ❌
B says "chlorine is less reactive than sodium bromide" — wrong ❌
C says "chlorine is more reactive than bromine" — correct ✅
D says "chlorine is less reactive than bromine" — wrong ❌
Answer: C
Question 10:
Let's check each option:
A. Cl + NaBr → NaCl + Br
Chlorine exists as Cl₂, not Cl (single atoms) ❌
B. Cl₂ + NaBr → NaCl + Br₂
Not balanced (2 Cl on left, only 1 Cl on right; 1 Br on left, 2 Br on right) ❌
C. Cl₂ + 2NaBr → 2NaCl + Br₂
Correct formulas ✅
Balanced ✅
Correct products ✅
D. Cl₂ + 2NaBr → 2ClBr + 2Na
Wrong products (ClBr is not formed; sodium metal is not produced) ❌