10 minutes maximum! Can you do it in 5?
1. A solution with pH 9 would be classified as a ...
  • A.  strong acid
  • B.  weak acid
  • C.  strong alkali
  • D.  weak alkali

2. What is the pH value of a neutral solution?

  • A. 0 
  • B. 1 
  • C. 7 
  • D. 14 

3. In aqueous solutions acids and alkalis produce ...

acids alkalis
A OH- ions H+ ions
B H+ ions OH- ions
C H atoms O2- ions
D O2- ions H atoms

4. Acids react to produce salts. The salts formed by hydrochloric, sulfuric and nitric acids are ...

  Hydrochloric acid Sulfuric acid Nitric acid
A chlorides sulfides nitrides
B chlorides sulfites nitrites
C chlorides sulfates nitrates
D chlorates sulfates nitrates

 

5. The word equation for the reaction between zinc and sulfuric acid is ...

  • A.  zinc  +  sulfuric acid   → zinc sulfide  +  hydrogen
  • B.  zinc  +  sulfuric acid  →  zinc sulfate  +  hydrogen
  • C.  zinc  +  sulfuric acid  →  zinc sulfide  +  water
  • D.  zinc  +  sulfuric acid  →  zinc sulfate  +  water

6.The products of the reaction between copper(II)oxide and hydrochloric acid are ...

  • A.  copper(II)chloride  +  water
  • B.  copper(II)chloride  +  oxygen
  • C.  copper(II)chloride  +  hydrogen
  • D.  copper(II)chloride  +  carbon dioxide
7. The chemical equation for the reaction between magnesium and hydrochloric acid is ...
  • A. Mg + HCl → MgCl + H
  • B. 2Mg + 2HCl → 2MgCl + H2
  • C. Mg + 2HCl → MgCl2 + 2H
  • D. Mg + 2HCl → MgCl2 + H2

Q8-9  A student wrote the following method for the preparation of copper(II)sulfate solution:

  1. Add 1 spatula of copper(II)carbonate to 50cm3 of sulfuric acid and stir
  2. Repeat step 1 until there is no more fizzing.


Crystal Titan | CC 4.0

8. The ‘fizzing’ is due to ...

  • A.  the formation of water
  • B.  the formation of carbon dioxide
  • C.  the formation of hydrogen
  • D.  vigorous stirring

9. To produce crystals of copper(II)sulfate the student should continue the experiment by ...

  • A.  ….filtering off the excess copper(II)carbonate then partially evaporating the solution and leaving to cool and crystallize
  • B.  …filtering off the excess copper(II)carbonate then evaporating the solution to dryness
  • C. ….decanting off the excess copper(II)carbonate then partially evaporating the solution and leaving to cool and crystallize
  • D.  ….decanting off the excess copper(II)carbonate then evaporating the solution to dryness

 

10. The reaction between sodium hydroxide and hydrochloric acid is a ...

  • A.  displacement reaction
  • B.  crystallization reaction
  • C.  condensation reaction
  • D.  neutralization reaction