Grab a calculator and a copy of the periodic table
(This test has only 10 questions, but may take 15  20 mins).
This test mainly covers calculations involving solutions 
1. The correct formula for the concentration of a solution in mol/dm^{3} is..
 A. concentration = number of moles x volume in cm^{3}
 B. concentration = number of moles x volume in dm^{3}
 C. concentration = number of moles ÷ volume in cm^{3}
 D. concentration = number of moles ÷ volume in dm^{3}


2. 100cm^{3} of a sodium hydroxide solution was prepared by dissolving 20g of sodium hydroxide, NaOH, in water.
What is the concentration of this solution in g/dm^{3}?
 A. 0.2 g/dm^{3}
 B. 5 g/dm^{3}
 C. 20 g/dm^{3}
 D. 200 g/dm^{3}


3. Which solution contains the greatest number of moles?
 A. 20 cm^{3} of 2.0 mol/dm^{3} hydrochloric acid
 B. 40 cm^{3} of 1.0 mol/dm^{3} hydrochloric acid
 C. 60 cm^{3} of 1.0 mol/dm^{3} sodium hydroxide
 D. 80 cm^{3} of 0.5 mol/dm^{3} sodium hydroxide


4. 1.0dm^{3} of ethanoic acid solution, CH_{3}COOH, contains 6.0 g of ethanoic acid
[Mr value of CH_{3}COOH = 60].
The concentration of the ethanoic acid solution, in mol/dm^{3}, is..
 A. 0.1
 B. 0.6
 C. 1.0
 D. 10


5. Sodium hydroxide solution can be neutralized using dilute ethanoic acid. The equation for the reaction is:
NaOH(aq) + CH_{3}COOH(aq) → CH_{3}COONa(aq) + H_{2}O(l)
Calculate the volume of 0.200 mol/dm^{3} ethanoic acid needed to exactly neutralize 0.0025 moles of sodium hydroxide solution. 

 A. 0.0125 cm^{3}
 B. 1.25 cm^{3}
 C. 12.5 cm^{3}
 D. 12.5 dm^{3}


6. 0.30 moles of barium chloride solution was added to 0.20 moles of magnesium sulfate solution in the following precipitation reaction:
BaCl_{2}(aq) + MgSO_{4}(aq) → BaSO_{4}(s) + MgCl_{2}(aq)
How many moles of barium sulfate, BaSO_{4}, would be produced?
 A. 0.20
 B. 0.25
 C. 0.30
 D. 0.50


Q710:
A student used a titration method to find the concentration of a solution of oxalic acid, H_{2}C_{2}O_{4}. The equation for the reaction is:
2NaOH(aq) + H_{2}C_{2}O_{4}(aq) → Na_{2}C_{2}O_{4}(aq) + 2H_{2}O(l)
She obtained the following results:
Volume of sodium hydroxide solution in conical flask 
25.0 cm^{3} 
Concentration of sodium hydroxide solution 
0.120 mol/dm^{3} 
Average volume of oxalic acid solution added 
18.30 cm^{3} 


7. Calculate the amount, in moles, of sodium hydroxide used.
 A. 3.00
 B. 0.00300
 C. 2.20
 D. 0.00220


8. Calculate the concentration, in mol/dm^{3}, of the oxalic acid.
 A. 0.328
 B. 0.164
 C. 0.0820
 D. 0.0440


9. The piece of apparatus used to measure the volume of sodium hydroxide is a
. 
10. The piece of apparatus used to measure the volume of oxalic acid is a
. 
